Set Theory - Homework 4 due 10/12/22

Click here to return to the main course web page.

Hand in 3 problems; do as many as you can. Any problem may use the previous problems as established fact.

\( \def\Ucal{\mathscr{U}} \def\Vbf{\mathbf{V}} \def\Ult{\mathrm{Ult}} \def\Mbf{\mathbf{M}} \def\jbf{\mathbf{j}} \def\Lbf{\mathbf{L}} \def\Pcal{\mathscr{P}} \)

A \(\Sigma_1\)-formula is a formula in the language of set theory of the form \(\exists u \phi(u,\bar v)\) where \(\phi\) is quantifier free. A \(\Sigma^1_2\)-formula is a formula of the form \[ \exists \bar u \in \Pcal(\omega)^m \forall \bar v \in \Pcal(\omega)^n \phi(\bar u,\bar v,\bar w) \] where all quantification in \(\phi\) ranges over \(\omega\).

  1. Prove that if \(\phi (\bar v)\) is a \(\Sigma_1\)-formula, then there is a \(\Sigma^1_2\)-formula \(\psi(\bar v)\) such that whenever \(\bar x\) is a tuple of subsets of \(\omega\) of the appropriate length, \(\psi(\bar x)\) is equivalent to \(H_{\omega_1} \models \phi(\bar x)\).

Let \(\mu\) be the Borel measure on \(\Pcal(\omega)\) determined by declaring \(\mu(\{A \subseteq \omega : n \in A\}) = 1/2\) for each \(n \in \omega\).

  1. Show that membership to \(\Pcal(\omega) \cap \Lbf\) and \(<_\Lbf \restriction \Pcal(\omega) \cap \Lbf\) are expressible by a \(\Sigma^1_2\)-formulas. Show that if \(\Pcal(\omega) \cap \Lbf\) is not measure 0, then \(<_\Lbf \restriction \Pcal(\omega) \cap \Lbf\) is a nonmeasurable \(\Sigma^1_2\)-set. Hint: use Fubini's Theorem.
    Remark: The map \(A \mapsto \sum_{n \in A} 2^{-n}\) is a measure preserving map from \((\Pcal(\omega),\mu)\) to \(([0,1],\lambda)\) where \(\lambda\) is Lebesgue measure. Moreover this map is one-to-one except on a countable (hence measure 0) set.

If \(\Ucal\) is an ultrafilter on a set \(I\), define a class relations \(\in_{\Ucal}\) and \(=_\Ucal\) on all functions with \(I\) by \[ f =_\Ucal g \textrm{ if and only if } \{i \in I : f(i) = g(i) \} \in \Ucal \] \[ f \in_\Ucal g \textrm{ if and only if } \{i \in I : f(i) \in g(i) \} \in \Ucal \] Let \(\operatorname{Ult}(\mathbf{V},\Ucal)\) denote the set of \(=_\Ucal\) equivalence classes of elements of \(\mathbf{V}^I\) equipped with the binary relation which \(\in_\Ucal\) induces on \(=_\Ucal\)-classes. Los's Theorem implies that the map from \(\mathbf{V}\) into \(\operatorname{Ult}(\mathbf{V},\Ucal)\) which sends \(x\) to (the equivalence class of) the function which is constantly \(x\) is an elementary embedding – it preserves the truth of first order formulas. In particular \(\operatorname{Ult}(\mathbf{V},\Ucal)\) is a model of ZFC.

  1. Show that \(\Ucal\) is closed under countable intersections if and only if \(\in_\Ucal\) is well-founded. Conclude that if there is an ultrafilter \(\Ucal\) is closed under countable intersections and is nonprinciple, then there is a transitive class \(\Mbf\) which contains the ordinals and an elementary embedding \(\jbf:\Vbf \to \Mbf\) which is not the identity (here \(\jbf\) is a class function).
  2. Show that if \(\jbf:\Vbf \to \Mbf\) is a nontrivial elementary embedding into a transitive class \(\Mbf\), then there is an ordinal \(\kappa\) such that \(\jbf(\kappa) \ne \kappa\). This ordinal is called the critical point of \(\jbf\).
  3. Show that if \(\jbf:\Vbf \to \Mbf\) is an elementary embedding with critical point \(\kappa\), then \(\{U \subseteq \kappa : \kappa \in \jbf(U)\}\) is a countably complete ultrafilter on \(\kappa\). Moreover, show that if \(U \in \Ucal\) and \(r:U \to \kappa\) is such that \(r(\alpha) < \alpha\) for all \(\alpha \in U\), then \(r\) is constant on a set in \(\Ucal\). An ultrafilter with this property is said to be normal.
  4. Show that the critical point \(\kappa\) of an elementary embedding \(\jbf :\Vbf \to \Mbf\) is a strongly inaccessible cardinal. Show moreover that the set of all \(\lambda \in \kappa\) such that \(\lambda\) is a strongly inaccessible cardinal is stationary in \(\kappa\). A cardinal which is the critical point of an elementary embedding \(\jbf : \Vbf \to \Mbf\) is called a measurable cardinal.
  5. Show that \(\Lbf\) satisfies ``there are no measurable cardinals.''