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Recurrence Relation

Denote by {pk | k=0,…,∞} the orthogonal polynomials obtained from {Pj3 | j=0,…,∞} by the Gram-Schmidt Process. The pk are antisymmetric orthogonal polynomials.

Define the polynomials ρj = Pj1 + R1(Pj1) + R2(Pj1), where R1 is rotation once CCW, and R2 is rotation twice CCW. Therefore, the ρj are fully symmetric polynomials.

Then we denote by {sk | k=0,…,∞} the orthogonal polynomials obtained from {ρj | j=0,…,∞} by the Gram-Schmidt Process. The sk are fully symmetric orthogonal polynomials.

And Green's function is defined so that if u solves Δu = f, then:

u(x) = − ∫ G(x,y) f(y) dμ(y)

We also define the inner product to be:

< f, g > = ∫ f(x) g(x) dμ(x)

Then we have the following main result.

Theorem 1

Let {pk | k=0,…,∞} be the orthogonal polynomials defined above. Let f0(x)=0 and for k≥0, let fk+1 be the polynomial of degree k+1 with leading coefficient 1 given by

fk+1(x):= − ∫ G(x,y) pk(y) dμ(y)

Set p-1(x):=0, and p0(x)=P03(x). Then, for each k≥ 0

pk+1(x) = fk+1(x) − bk pk(x) − ck pk-1(x)

where

bk = dk2 < fk+1,pk > ,

ck= dk-12 / dk2 = ||pk||2 / ||pk-1||2

Consequently,

dk-2 = ||pk||2 = d0-2 c1 c2 c3 … ck-1 ck

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Then, by normalizing the pk, we get the orthonormal polynomials Qk:

Qk = dk pk = pk / ||pk||

By a similar procedure, we can calulate the sk and their orthonormal counterparts Sk.

Furthermore, we note here that the Sk and the rotations of the Qk form a tight frame for their span in Hj, k≤j. As a result, we define the fully orthonormal polynomial φk by:

φk = √(2/3) Qk + √(1/3) Sk

Note that φk and its rotations for k≤j form an orthonormal basis for Hj